My arithmetic sequence

carsong2016 on September 10, 2018

$t_1$ = 3, $t_2$ = 10, $t_3$ = 17, $t_4$ = 24, $t_5$ = 31.

So 3, 10, 17, 24, 31…

$t_{50}$ ? $S_{50}$ ?

what I would do first is find out what is $t_{50}$ .

$t_n$ = $t_1$ +(n-1)d

$t_{50}$ =3+49(7)

$t_{50}$ =3+343

$t_{50}$ =346

Now I need to find $S_50$ .

$S_n$ = $\frac{n}{2}$ ( $t_1$ + $t_{50}$ )

$S_{50}$ = $\frac{50}{2}$ (3+346)

$S_{50}$ =25(349)

$S_{50}$ =8725

So $t_{50}$ =346 and $S_{50}$ =8725.

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