I learned how to determine if a relation is a function. There are two ways that I know of to prove if its a function. Firstly, one way is to see if a input shows up more then once. Every input is mapped out to exactly one output. However, two different inputs can have different outputs just as long as the inputs are different. The other way to figure out if a relation is a function is the Vertical Line Test. If you draw a vertical line that intersects at only one point of the graph, it is a function. If it intersects more than once then it’s not a function. The only real challenge is paying attention on a graph or in ordered pairs, because its easy to get things mixed up.
Monthly Archives: May 2017
Week 13 – The X and Y Intercepts
X intercept- A point on a graph where the graph intersects the x-axis and the x intercept happens on the point of the graph where the y-coordinate is zero.
Y intercept- A point on a graph where the graph intersects the y-axis and the y intercept happens on the point of the graph where the x-coordinate is zero.
You apply these two when it comes to solving equations on a graph, determining it algebraically. A challenge that I see myself doing is remembering which value is zero, either x or y. Another challenge is sometime solving it algebraically can be confusing for one. You would use this on a graph and finding values for the following intercepts.
Zack’s Character Profile
Aaron’s Future Lifestyle
Week 11 – Using the box method when factoring trinomials
This week I learned a new method of factoring trinomials. It is the box method. You would really only need this when a doesn’t equal one in a equation.
Example:
For this method you make a for sided box with the highest term in the top left and the lowest one on the bottom right. 
You multiply the two to get the number that two numbers have a product a sum of. (The middle term bx)
Then you find two numbers that fit.
Then you go and find what the terms have in common, if they dont have anything in common you put one. And to find something that thet do have in common you find the gcf.
Then you simply right out the factored equation.
Some challenges are; when the positives and the negatives are implemented to the equation, it can be confusing. Another challenge is finding the correct numbers that fit.