Category Archives: Math 10

Week 14- Determining if a Relation is a Function

I learned how to determine if a relation is a function. There are two ways that I know of to prove if its a function. Firstly, one way is to see if a input shows up more then once. Every input is mapped out to exactly one output. However, two different inputs can have different outputs just as long as the inputs are different. The other way to figure out if a relation is a function is the Vertical Line Test. If you draw a vertical line that intersects at only one point of the graph, it is a function. If it intersects more than once then it’s not a function. The only real challenge is paying attention on a graph or in ordered pairs, because its easy to get things mixed up.

Week 13 – The X and Y Intercepts

X intercept- A point on a graph where the graph intersects the x-axis and the x intercept happens on the point of the graph where the y-coordinate is zero.

Y intercept- A point on a graph where the graph intersects the y-axis and the y intercept happens on the point of the graph where the x-coordinate is zero.

You apply these two when it comes to solving equations on a graph, determining it algebraically. A challenge that I see myself doing is remembering which value is zero, either x or y. Another challenge is sometime solving it algebraically can be confusing for one. You would use this on a graph and finding values for the following intercepts.

Week 11 – Using the box method when factoring trinomials

This week I learned a new method of factoring trinomials. It is the box method. You would really only need this when a doesn’t equal one in a    equation.


For this method you make a for sided box with the highest term in the top left and the lowest one on the bottom right.  You multiply the two to get the number that two numbers have a product a sum of. (The middle term bx)

Then you find two numbers that fit.

Then you go and find what the terms have in common, if they dont have anything in common you put one. And to find something that thet do have in common you find the gcf.

Then you simply right out the factored equation.

Some challenges are; when the positives and the negatives are implemented to the equation, it can be confusing. Another challenge is finding the correct numbers that fit.

Title – Week 10 Factoring Trinomials by Inspection

Factoring trinomials in this form : 

To do this by inspection you need to find two integers which have a product of c and a sum equal to b.


You need to identify what two numbers have a product of 20 and has a sum of 21. In many this case 20 has many possibilities for the sum and a product,, this can be a challenge. For example 4 & 5 equals to 20 as a product, however their sum is only 9 so that wouldn’t work. What would work though would be 1,20, because they make a product of 20 and have a sum of 21. Then what you need to do is factor and write out the equation


You know that this is correct when you foil the term and get the same equation.

Week 8 – Using FOIL for the Distributive Property

I learned how to use FOIL :

F-First term in each bracket

O- Outside terms

I- Inside terms

L- Last term in each bracket

You apply it when you multiply two binomials. Example:

 First you multiply the first terms of each bracket. (x()x) 

Then you multiply the outside term with the first term in the first bracket. (x)(2) 

Then you multiply the inside term from the first bracket with first term in the second bracket. (2)(x) 

Then you multiply the last term in each bracket. (2)(2)=4

The last step is to add like terns and to simplify.



Some challenges are getting the order confused.


Week 7 – Labeling a Triangle using SOH CAH TOA

This week I learned how to label the sides of a triangle and to find the angles using trigonometry. Using SOH CAH TOA you can find these all without using Pythagorean theorem. A challenge can be correctly labeling the Adj., Opp., and the Hyp. Another one is getting the wrong formula SOH CAH TOA. And another challenge is not doing the right calculations on a calculator. This is applied when you are finding the sides or angles of a triangle.

For this example I’ll show how to find X(Hyp.) and angle A and angle B.


For this you really need to label it correctly on what angle you want to find. First Angle A.




Then Angle B..

With these angles you can now find X(Hyp). As long as don’t use Tan. again you will get the same answer. Also as long as you use the formula correctly.