This week I learned how to determine weather a point is going to be a solution in a inequality.
First you have to move either x or y over, in this case the y was easier to move because it was originally negative. After you move your x or y over, then you plug in the point that you have to find out if it’s a solution or not. If you plug everything in and solve, it’ll be a solution if the inequality is true.
This week I learned how to use standard form, from standard form you can find the vertex, and to find the y intercept, you just plug in 0 where x is and solve for the rest of it. If you find where the parabola opens and where the vertex is, you can tell how many x intercepts there will be, in this question the parabola opens up and the vertex has both positive numbers so there were no x intercepts.
This week I learned how to find the discriminant. To find the discriminant, you take the b2 – 4ac
from the original quadratic formula, the discriminant is how you can find out how many roots the quadratic equation is going to have. If the discriminant above 0 it will have 2 roots, if the discriminant is 0, you will have 1 root, and if the discriminant is negative, there are no roots.
This week I learned how to use the table of values in a quadratic function to find the vertex and x intercepts. You can find the vertex on the table of values by plugging x into the function and then on the table of values you look for either the highest or the lowest point on the y.
