Sequence: 1, 5, 9, 13, 17
Difference: 4
Finding :
= + (n – 1)(d)
= 1 + (50 – 1)(4)
= 1 + (49)(4)
= 197
Finding the sum of the first 50 terms:
= ( + )
= (1 + 197)
= 25(198)
= 4950
Sequence: 1, 5, 9, 13, 17
Difference: 4
Finding :
= + (n – 1)(d)
= 1 + (50 – 1)(4)
= 1 + (49)(4)
= 197
Finding the sum of the first 50 terms:
= ( + )
= (1 + 197)
= 25(198)
= 4950