This week in math we learned how to determine the points of intersection of a linear absolute value equation, for example
:|2x-3|=9
the first is to split the equation into separate ones. one of them you have to replace the absolute value signs with brackets then place a negative in front that has to be distributed followed by solving as shown below.
-(2x-3)=9
-2x+3=9
-2x=6
x=-3
The second step is to just remove the absolute value signs from the equation then solve
2x-3=9
2x=12
x=6
you can now determine that for the two points of intersection x would equal x=-3 and x=6