Year: 2019
Three Philosophers
The author of this article had been invited by one of his colleagues to join him in setting up a booth at the entrance of a subway station in New York. I enjoyed this article because it was interesting to know the types of questions that people wanted to ask. It was revealed that there are many people who are not sure about what they should start doing with their lives. In this article the philosophers explored what it is that gives life meaning, what we can do to make ourselves happy, and other ideas about human nature. I recommend this article because of it’s interesting topic, and because it was fun to read.
Measuring Keq Lab
Measuring Keq
Part I: Preparation of a standard absorption curve for FeSCN+2
Standard | 0.20M Fe(NO3)3 | 0.0020 M KSCN | 0.100M HNO3 | [FeSCN+2] | Absorbance |
A | 10.0 mL | 0.0 mL | 15.0 mL | 0M | 0.000 |
B | 10.0 mL | 1.0 mL | 14.0 mL | 8.00×10^-5M | 0.307 |
C | 10.0 mL | 1.5 mL | 13.5 mL | 1.20×10^-4M | 0.446 |
D | 10.0 mL | 2.0 mL | 13.0 mL | 1.60×10^-4M | 0.616 |
E | 10.0 mL | 2.5 mL | 12.5 mL | 2.00×10^-4M | 0.815 |
F | 10.0 mL | 3.0 mL | 12.0 mL | 2.40×10^-4M | 0.965 |
EQUATION: y=3966.9x R2 0.9968
Part 2: Measuring Equilibrium
Test Solution | 0.0020 M Fe(NO3)3 | 0.0020 M
KSCN |
0.10 M
HNO3 |
Initial [Fe+3] | Initial [SCN–] | Absorbance | Equilibrium
[FeSCN+2]* |
I | 5.0 mL | 0 | 5.0 mL | 0.0010M | 0M | 0 | 0M |
II | 5.0 mL | 1.0 mL | 4.0 mL | 0.0010M | 2.0×10^-4M | 0.172 | 4.33×10^-5M |
III | 5.0 mL | 2.0 mL | 3.0 mL | 0.0010M | 4.0×10^-4M | 0.404 | 1.02×10^-4M |
IV | 5.0 mL | 3.0 mL | 2.0 mL | 0.0010M | 6.0×10^-4M | 0.642 | 1.62×10^-4M |
V | 5.0 mL | 4.0 mL | 1.0 mL | 0.0010M | 8.0×10^-4M | 0.845 | 2.13×10^-4M |
VI | 5.0 mL | 5.0 mL | 0.0 mL | 0.0010M | 1.0×10^-3M | 0.904 | 2.28×10^-4M |
* To be determined from the standard graph equation.
ANALYSIS:
- Use your graph equation to calculate the equilibrium concentrations of FeSCN+2.
- Prepare and ICE chart for each test solution (II – VI) and calculate the value of Keq for each of your 5 tests solutions.
ICE CHART 1
Test Solution
Keq =282 |
Fe3+ + SCN– ⇄ FeSCN2+ | ||
I | 0.0010 | 0.00020 | 0 |
C | -0.0000433 | -0.0000433 | +0.0000433 |
E | 0.00096 | 0.00016 | 0.0000433 |
ICE CHART 2
Test Solution
Keq =378 |
Fe3+ + SCN– ⇄ FeSCN2+ | ||
I | 0.0010 | 0.00040 | 0 |
C | -0.000102 | -0.000102 | +0.000102 |
E | 0.00090 | 0.00030 | 0.000102 |
ICE CHART 3
Test Solution
Keq =444 |
Fe3+ + SCN– ⇄ FeSCN2+ | ||
I | 0.0010 | 0.00060 | 0 |
C | -0.000162 | -0.000162 | +0.000162 |
E | 0.00083 | 0.00044 | 0.000162 |
ICE CHART 4
Test Solution
Keq =444 |
Fe3+ + SCN– ⇄ FeSCN2+ | ||
I | 0.0010 | 0.00080 | 0 |
C | -0.000213 | -0.000213 | +0.000213 |
E | 0.00080 | 0.00060 | 0.000213 |
ICE CHART 5
Test Solution
Keq =384 |
Fe3+ + SCN– ⇄ FeSCN2+ | ||
I | 0.0010 | 0.0010 | 0 |
C | -0.000228 | -0.000228 | +0.000228 |
E | 0.00077 | 0.00077 | 0.000228 |
CONCLUSION AND EVALUATION:
- Comment on your Keq values. Do your results convince you that Keq is a constant value regardless of the initial concentrations of the reactants? Why or why not?
Yes, because most of the values we got for Keq are fairly close to each other.
- Calculate the average value of Keq from your five trials. The actual value of Keq for this reaction at 25oC is reported as 280. Calculate (should you use all of your values?) the percent difference of your average value from the reported value:
% difference = (experimental value – reported value) x 100%
Reported value
Average = Keq1 + Keq2 + Keq3 + Keq4 + Keq5
5
Average = 282 +378 + 444 + 444 + 384 = 386
5
% difference = (386-280) x 100% = 37.9%
280
Desmos Art Functions Card 2018
https://www.desmos.com/calculator/jqfcmzmvkx
Working on this project was a good way to review what we have worked on during the semester. I started the card by graphing a pineapple, because I really wanted there to be a pineapple on the card. i then made a plan for what the rest of the card would look like, and started thinking about what kind of functions should be used for each shape. When I couldn’t get the shape of a line right, I started experimenting with different stretches until I could get the shape I was looking for. I had a problem while shading, I wanted a colour that wasn’t an option in desmos, then I found out that I could layer the different colours on top of each other to get what I wanted. This assignment helped me review what we have worked on earlier in the semester, and it has helped me find out what I should start reviewing for the finals.