laTex coding

Posted on October 2, 2024 by Ms.Burton

$\frac{3}{4}$

$-2\frac{1}{7}$

$18^{32}$

$2^4\cdot2^8=2^{4+8}=2{12}$

$x^7\div x^3=\frac{x^7}{x^3}=x^{7-3}=x^4$

$\angle B=90^{\circ}$ $\triangle ABC$ $\sin\theta$

$\cos42^{\circ}$

$12 = 2\cdot 2\cdot 3$

$\sqrt{25}$

$\angle ABC$

$\triangle CDE$

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