writing trig equations

Posted on March 5, 2017 by Ms.Burton

$\sin60^\circ= \frac{x}{2}$

$\tan A= \frac{5}{9}$

$\frac{\sin20^\circ}{90} = \frac{\sin B}{45}$

$a^2=b^2+c^2-2bc\cos A$

$a=\sqrt{b^2+c^2-2bc\cos A}$

$\angle A= 57^\circ$

This entry was posted in LIF. Bookmark the permalink.

Leave a Reply Cancel reply