I am going to show one of the many ways to take out the GCF in a polynomial expression.
When you see your initial expression, you wont to ask what is the biggest number I can take out of all of the numbers? You can take out 5x from all of them… Put it on the side of the box. Then what multiplied by 5x is going to give you the numbers inside… These you put directly over the number in the box. Once found you have all the factors of what is inside the box.
This week was factoring polynomials and atbthe beginin it was a lot to take in but by the end I think i got the hang of it.
It really helped when Ms.Burton showed us we can factor usin an Area Model and it was a lot easier for me.
I have drawn out the steps to find the factors of an expression:
This shows the first step, you are given an expression…
(What i’m showing will only work if it looks like this; x to the power of 2/ squared and the middle is a number followed by x and then the last just a constant term or a number with no variable or degree.)
the next step is to list the factors of the constant (in yellow.) then find the one that fits best for the sum of the middle number. place the x squatted in the top left and the constant in the bottom right box then the two numbers that add to 21 in the remaining.
Solve for what the highest number or variable is that you can take out of each two boxes. I have shown arrows and then the answers.
Now the numbers on the outside is your answer, all the factors of the first expression. Therefore your answer is….
In Math 10 this week we started Trigonometry. It is pretty straight forward one you have labeled correctly. I will be demonstrating finding a missing side length using Sine, Cosine, or Tangent. Keeping SOHCAHTOA in mind. I have created a video that will show step by step how to solve for a missing side length.
Getting heavier into measurement we received a formula sheet, one that we can use on tests and in the homework so we do not have to memorize all of them. This was very helpful and much appreciated. Unfortunately we had to remember one or two things; finding the slant hight of something with a triangular shape or comes to a point and the formulas for hemi-spheres.
I am going to demonstrate finding the slant height of something with a triangular shape or a shape that comes to a point. There are different shapes you might need find the slant hight for, like a pyramid or a cone.
First lets see the shape we will be using… A cone!
A cone is a shape that looks like a flipped ice cream cone.
Next you will be given some measurements, before this you should know the names of measurements that you need to know.
Blue- the true height
Red- slant height
(the radius is half of the diameter)
Now lets say, you have been giving some measurements…
So, you have been given the True Height and the Diameter, but need to find the slant height…
You have to follow a formula that calls for the radius to be involved, we already know that the radius is half of the diameter therefore..
Our radius is 6.
To find the slant height you need to follow a formula…
h = true height
r = radius
s= slant height
Now you simply plug in the numbers you know into the formula.
Solve what you can… And get your answer!
The Slant Height is equal to 10. The slant height is 10cm.
This week in Math 10 we started our Measurement Unit. I learned that estimating can now become a bit more accurate just by using our body to measure things. It also helps if you know the measurements of the body parts you are using to estimate the real size.
Large Objects – Face of your Fridge:
You could use the width of your body (shoulder to shoulder) and measure the face that way.
Medium/ Regular Objects – Computer Face:
You could use the width of your hand (edge of pinkie to edge of thumb) and measure the face that way.
Small/ Tiny Objects – Plastic Water Bottle Cap:
You could use the height of coins stacked (dimes are good) and measure the height that way.