This week we learned how to do substitution and elimination. My favourite strategy is elimination. Both substitution and elimination are used to find the point of intersection in 2 equations.

Ex.  8x-3y=6

6x+12y=-24

The first think you do is make zero pairs. We can multiply 8x, -3y and 6 by 4 to create a zero pair so that -3y equals -12y. -12y and +12y equals 0.

Now our equation is simplified to 32x=24 and 6x=-24. We will now add these equations together to equal 38x=0. We want to isolate x so we will divide 38/38 and 0/38. x=0.

To find y, we will put a 0 wherever there is a x in the original equation and isolate to find y. 8(0)-3y=6. -3y=6 and then, y=-2.