Week 2 – Precalc 11

This week in math we learned how to find the sum of a geometric sequence. To do this you have to use the formula:

s=\frac{a(r^n -1)}{r-1}

so if you were given the geometric sequence 6, 24, 96, 384… and you want to find s_{15} you would do the following

\frac{24}{6} which means r= 4

once you know what r is you would use the formula shown above

s_{15}=\frac{6(4^{15}-1)}{4-1}

 

s_{15}=\frac{6(1,073,741,824-1)}{4-1}

 

s_{15}=\frac{6(1,073,741,823)}{4-1}

 

s_{15}=\frac{6,442,450,938}{4-1}

 

s_{15}=\frac{6,442,450,938}{3}

 

s_{15}=2,147,483,646

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