For this project i like my writing and the real legal document included but i think i could’ve worked harder on the outwards appearance of the actual journal.
Category: Grade 10
Math Week 15
Using the formula y2 – y1/x2 – x1 to find slope
Ex. (5,-7)(7,5)
y2 – y1 is the y value of the second pair minus the y value of the first pair. In this case: 5 – (-7) which is equal to 5+7 = 12
x2 -x1 is the x value of the second pair minus the x value of the first pair. In this case: 7-5 = 2
This becomes 12/2 which is equal to 6
Math Week 14
Finding the slope from two point on a graph
The formula for slope of a line is rise/run
Ex. (-1,6)(2,8)
To get from (-1,6) to (2,8) on a graph you have to go up the Y axis 2 and across the X axis 3
Which makes your Rise/Run: 2/3
The slope of this line is 2/3
Math Week 12
The X value is also the independent variable and input
The Y value is also the dependent variable and output
When you’re looking at a set of all X values its called the Domain
When you’re looking at a set of all Y values its called the Range
A Function is a relation where each input (x value) is only related to one output (y value)
However it doesn’t matter if the outputs are related to more than one input
Math Week 11
Finding the GCF in polynomials
(4x^2y)(8x^3y)
expand (4x^2y) into (2)(2)(x)(x)(y)
expand (8x^3y) into (2)(2)(2)(x)(x)(x)(y)
The numbers that the expanded version have in common are:
(2)(2)(x)(x)(y)
when you multiply these together you end up with 4x^2y which is your greatest common factor
Math Week 9
Greatest Common Factor in polynomials
If the expression has numbers that have common factors you can pull them out.
4x – 8 + 6
The greatest common factor here would be 2 which means the polynomial would become:
2(2x – 4 + 3)
Math Week 7
Using SOH CAH TOA to find the side of a right angle triangle
Say you have a triangle where you know an acute angle and the hypotenuse and you’re trying to find the opposite side. You would use Sin. (SOH Sin Opposite Hypotenuse)
Ex. Sin 39 = x/9
(9)Sin39 = x/9(9)
x = 5.7
(39 = angle, x = opposite side, 9 Hypotenuse)
Math Week 5
The formula for the surface area of a sphere is 4Pi(r)^2
The formula for the volume of a sphere is V=4/3πr^3
Math Week 3/4
This week we learned about Exponent Laws.
When you’re multiplying two numbers with exponents, you add the exponents together. When you’re dividing two numbers with exponents, you subtract the exponents. If there is two exponents to one number {ex. (3^2)^4 } you multiply the exponents together.
Math Week 6
The formula for surface area of a cone is (Pi)(radius^2) + (Pi)(Radius)(Slant)
To find the slant height you can use the radius, height and unknown slant height to make a right triangle. Then use the Pythagorean theorem to find the missing side.