## myCBSEguide App

CBSE, NCERT, JEE Main, NEET-UG, NDA, Exam Papers, Question Bank, NCERT Solutions, Exemplars, Revision Notes, Free Videos, MCQ Tests & more.

Install Now

NCERT Solutions for Class 10 Maths Exercise 2.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

**NCERT solutions for Class 10 Maths Polynomials Download as PDF**

## NCERT Solutions for Class 10 Maths Polynomials

**1. Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in each of the following.**

**(i), **

**(ii), **

**(iii), **

**Ans. (i)**

Therefore, quotient = x – 3 and Remainder = 7x – 9

**(ii) **

** **

Therefore, quotient = and, Remainder = 8

**(iii)**

** **

Therefore, quotient = and, Remainder = −5*x *+ 10

NCERT Solutions for Class 10 Maths Exercise 2.3

**2. Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial. **

**(i) **

**(ii) **

**(iii) **

** Ans. (i)**

Remainder = 0

Hence first polynomial is a factor of second polynomial.

**(ii)**

Remainder = 0

Hence first polynomial is a factor of second polynomial.

**(iii)**

Remainder ≠0

Hence first polynomial is not factor of second polynomial.

NCERT Solutions for Class 10 Maths Exercise 2.3

**3. Obtain all other zeroes of if two of its zeroes are and .**

**Ans. **Two zeroes of are and which means that is a factor of .

Applying Division Algorithm to find more factors we get:

We have

⇒

= ()

= ()3

= 3()

= 3()(*x*+1)(*x*+1)

Therefore, other two zeroes of are −1 and −1.

NCERT Solutions for Class 10 Maths Exercise 2.3

**4. On dividing by a polynomial g(x), the quotient and remainder were (x-2) and (-2x+4) respectively. Find g(x).**

**Ans. **Let, q(x) = (x – 2) and r(x) = (–2x+4)

According to Polynomial Division Algorithm, we have

p(x) = g(x).q(x) + r(x)

⇒ = *g*(*x*).(*x*−2)−2*x*+4

⇒ −4 = *g*(*x*).(*x*−2)

⇒ = *g*(*x*).(*x*−2)

⇒ *g*(*x*) =

So, Dividing by (*x*−2), we get

Therefore, we have *g*(*x*) =

NCERT Solutions for Class 10 Maths Exercise 2.3

**5. Give examples of polynomials p(x), g(x), q(x) and r(x), which satisfy the division algorithm and **

**(i) deg p(x) = deg q(x) **

**(ii) deg q(x) = deg r(x)**

**(iii) deg r(x) = 0**

**Ans. (i)** Let , g(x) = 3

So, we can see in this example that deg p(x) = deg q(x) = 2

**(ii)** Let and

We can see in this example that deg q(x) = deg r(x) = 1

**(iii)** Let, g(x) = *x*+3

We can see in this example that deg r(x) = 0

## NCERT Solutions for Class 10 Maths Exercise 2.3

NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

## CBSE app for Class 10

To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through **the best app for CBSE students** and myCBSEguide website.

Good solution

good solution but first q 2

he is best study

THANKSQ

Very helpful….

thanks a lot..????

It is really helpful …….

Thanks a lot …..

?

It is really helpful …….

Thanks a lot …..

?

It is really helpful …….

Thanks a lot …..

?

Amazing solution. …….

Tq ….

very nyc and easy to understand…..thank u so much

Very helpful……nd easy to understand

Good enough…….loved it?

Its very useful… Thanks…

Thanks a lot . It really helped me to score better marks in our exam.

Nice it is so help full

It is very helpful for me.

Thank you so much .