This week I learned how use substitution to find the solution of a system to first off you should look at one of the equations and isolate the variable that has a coefficient of either 1 or -1 to make it easier then it should look something like this 2y-3=x then in the other equation substitute the same variable you isolate into it so it would look like this 2(2y-3)+3y=6 and then isolate the y which would equal to this y=12/7 now we now that the solutions y is 12/7 we just have to input it into the original equation to find the x which is x=3/7 so the solution is          (3/7, 12/7).  you can also find the solution by simply plotting the linear equation on a graph and finding the points that match. you can also do elimination by simply multiplying either one or both equations so that either when the x or y s of both added together equals zero and the combining it altogether and isolating the non zero coefficients to get an answerhttps://myriverside.sd43.bc.ca/spencerd2021/wp-admin/post.php?post=634&action=edit#