Week 6 – Math 11 – Solving Quadratic Equations by Factoring

A quadratic equation is an equation with a squared/second degree term. IN a quadratic equation, the degree must be no higher than 2 and must be able to be written as:

ax^2 + bx + c = 0

where a, b, and c are coefficients and x is the variable.

To solve a quadratic equation by factoring, we need to factor the equation the same as we would factor any other trinomial by finding two numbers that multiply to give c and add to give b.

Ex. x^2 + 5x + 6 = 0.

Identify the coefficients a, b, and c. In this case, a = 1, b = 5, and c = 6.

Then you find two numbers that multiply to give c (6) and add to give b (5). In this case, we can use 2 and 3: 2 \cdot 3 = 6 and 2 + 3 = 5.

Then you use the two numbers to factor the quadratic equation.

x^2 + 5x + 6 = (x + 2)(x + 3) = 0

Now that our trinomial is factored, we need to solve x. To solve x, we can use the rule that anything multiplied by 0 will equal 0 meaning that if one of our binomials equaled 0, the whole equation would equal 0.

0(x + 3) = 0 or (x + 2)0 = 0

What we need to do now is to get any of our binomials to equal 0

(x + 2)(-3 + 3) = 0 or (-2 + 2)(x + 3) = 0

This shows that we have multiple answers being:

x = -2 and x = -3

Now we just verify our solution by substituting our answer(s) into x.

x^2 + 5x + 6 = (-2)^2 + 5(-2) + 6 = 0

 

x^2 + 5x + 6 = (-3)^2 + 5(-3) + 6 = 0

 

Easy.

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