This week in math we continued trigonometry, we practiced sin,tan,cos -1.  When using the sin/tan/cos -1 you are given a triangle with two side lengths.  Such as this triangle we are given 16.2 and 29.3.  The first thing I did was label the H, O, and A.  The two side lengths given were the adjacent side and the opposite so it is tan -1.  The equation would be solved by having 29.3/16.2 due to SOH CAH TOA, 29.3/16.2=1.8, now we can multiply 1.8 by tan-1 on our calculator and find out the angle we are looking for is 61 degrees.