This week we spoke about quadratic equations and how to find the variable, most commonly shown as X. We use tactics like FOIL and factoring to find the answers to X. While working with quadratic equations, there is usually two answers to X unless it is a special case where both answers to X are the same number, which is uncommon.

A quadratic equation where there is only one answer could look something like (x²+8x+16=0). In this question, to find X you must factor the equation. Taking the equation on the left and factoring it into looking like (x+4)(x+4) = 0. Then, you find the ways for this equation to equal zero. Since -4+4=0, then that would make the equation correct, but this works for both the brackets, making the only answer X =-4.

If you come across an equation where one side does not equal zero, then you need to move numbers to the other side of the = to make a side equal to zero to find the most answers for X.

In the equation x² + 11x = -28. you would need to make one side equal to zero by moving over numbers. It would b easiest to move over the -28. Another thing is that when you move a number to the other side of = it must turn into its opposite. The equation would then turn into x²+11x+28=0.
From here you factor the left side of the equation, using a box if you need to. Turning it into (x+7)(x+4)=0