The slope is the steepness of a line. On positive slopes the line rises from left to right where as on negative slopes the line decreases from right to left. (M) is the variable for slope and rise is (X) and run is (Y)

Slope Formula:

M= Rise (x) / Run (y)

M= y1-y2 / x1-x2

 

This week we learned about domain and range. In the beginning I didn’t really know what to do with inputs and outputs but when we got deeper into the lesson and did more examples I started to get it a little more. Abide by the BEDMAS rule when solving a function, you also replace the variable with the number given for the (x) value.

Domain: the independent(input) variable in the relation.

Range: the set of all numbers for the dependent(output) variable in the relation.

Function: a special realtion where every input(x) has only one output(y).

Function Notation:

 

 

To find the X intercept you make Y equal to 0. Essentially you want to isolate X in order to find what it is equal to. When finding the Y intercept it is nearly the same thing except you replace X with 0 in order to isolate Y to find what it is equal to.

When you write the X intercept in ordered pair form you but the X value first followed by Y (which should be 0).

ie:            (-4, 0)

Same with if you’re writing out the Y intercept in ordered pair form, you put the Value as 0 and plug in the Y value.

ie:               (0, 13)

When you have these two points you can begin to place them on a graph.

I chose to go over the distributive property because I forgot about this unit when going over the review package as well as the numbers unit. In distributive property you multiply the constant by the contents inside the brackets. Make sure your work is neat and tidy so you don’t get lost in bigger equations. I like to colour coordinate my terms so Its easier for me to decipher which terms I can group and which I cannot.

This week we learned how to factor trinomials. When factoring trinomials you want the first and last term to be the product of two numbers and the middle term to be the sum of two numbers. if there is no number that can add up to the number in the middle and multiply to the last term then the trinomial is unfactorable.

The first thing you want to do when removing the GCF in a trinomial is find all the factors of each number. Each number that has similar factors you can begin to remove, you want to place the factor you chose and move it outside of the brackets as well as dividing that number out of the trinomial, the number you get from dividing the factor goes inside the brackets. This makes factoring much easier. I chose simple examples which in my first example my numbers were 5, 15, and 10 and the factor I removed and divided by was 5x because in the trinomial each number had (X) in it. In my second example I had numbers 6, 9, and 18 and I removed 3 and divided each number by 3.