Math 10 Week #7

 This week, we learnt how to find angles and side lengths of triangles. In the picture, I did 3 different possible equations you might use in trigonometry.

In the first one, I had to do a cosine to find the angle because I already knew the adjacent and the hypotenuse of the triangle. The first thing you do is write out the equations which is cos x = \frac{3}{10} After that, you want to get x all by itself so, you divide cos x by cos to get x by itself. What you do to one side, you have to do to the other so we have to divide \frac{3}{10} by cos as well. Next, we bring the cosine to the top of the fraction so that you can multiply it with the fraction which makes it have a negative exponent of -1. Now all you need to do is multiply the two together to find x.

In the second equation, I’m trying to find the opposite side of the triangle. To do that, I knew that my equation would be a sin ratio so, the equation is sin 52 = \frac{x}{14}. From there, you have to get the x by itself. To do that, you multiply x by 14 to cancel 14 out and then do the same thing on the other side of the equation. Now, the equation is 14(sin 52) = x  Then, you answer the equation by multiplying to get 11m = x

In the third example, I am trying to find the hypotenuse and I already have the adjacent so I know that it’s going to be a cosine ratio. My equation is cos 64 = \frac{35}{x}. In order to get x by itself you have to reciprocate the fraction which means that you also have to do that on the other side. The equation is now \frac{1}{cos 64} = \frac{x}{35}. Then you have to multiply x by 35 and multiply the 1 by 35 on the other side as well. So now, \frac{35}{cos 64} = x. Now, we can solve the equation to find out that 79.8cm = x

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