Week 11 – Pre Calculus 11

This week in pre-calculus 11 we learned about graphing inequalities in 2 variables. One thing you must remember is that solutions for inequalities are shown on a number line and solutions for linear equations are represented on the axes lines on a graph (x,y). When graphing solutions to linear inequalities in 2 variables, they are represented by the boundary line and the shading of one side.

For the symbols that include an equal to the boundary line is solid (____). For the symbols that don’t include the equal to the boundary line is broken (—–  —–).

When graphing a inequality the first thing you do is find your y-intercept and slope, then you add the boundary line according to the type of inequality, and finally you shade the side the side of the boundary line that includes the possible solutions. When finding out what side to shade you must test certain points of the graph. These points can not be on the boundary line. Whichever side give a true statement you know that is the side you will shade.

Example: y\le2x+5

First you graph it like a regular linear equation, then you add the solid line because it’s y\le

Then you test a point on the graph, I tested (0,0) -> 0\le2(0)+5 -> 0\le5 . Which is a true statement therefore we shade that side of the line.

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