Week 2 – Geometric Sequences

This week in Pre-calculus 11 I learned about geometric sequences and how to use the formulas to isolate variables. In a geometric sequence each term is multiplied by a constant, known as a common ratio.

My geometric sequence:

3, 12, 48, … 49152

from this sequence we know:

  • t_1=3
  • t_n=49152
  • r = 4

To find r we use the formula, r=\frac{t_n}{t_{n-1}}, so:

  • r=\frac{t_n}{t_{n-1}}
  • r=\frac{12}{3}
  • r = 4

In this sequence we are trying to find what n is. To do that we would use the general formula used to find t_n :

t_n=(t_1)(r)^{n-1}, we then input all information that we already know.

  • t_n=(t_1)(r)^{n-1}
  • 49152=(3)(4)^{n-1}

we then need to divide everything by 3 to make it easier for us to isolate n.

  • [49152=(3)(4)^{n-1}]/3
  • 16384=4^{n-1}

To then find n you keep multiplying 4 by different powers until it matches the value of t_n divided by t_1. In this case we would multiply 4 by different powers until we get 16384.

  • 16384=4^{7}

If we know tat the power is 7 then that means that we know, 7 = n -1. We now know that n = 8 because 8 – 1 = 7.

 

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