this week we have learned one of the method of solving a pair of a linear system, substitution. A linear system is defined as two linear equations line that will meet the same point on a graph. It also means that they both have the same x and y value. In order to find x and y, the easiest method is substitution.

for example, given a set of linear systems

2x-3y=-2   4x+y=24

1. we will first need to isolate y at one side, makes the equation as “y=-4+24”.

2. after that we have to sub the “y=-4+24” into 2x-3y=-2, therefore will becomes 2x-3(-4+24)=-2, we calculate this equation and found out that x=5.

3. now sub back the x=5 into 4x+y=24 and we will get y=4

Then the solution of the points x,y will be (5,4).

But are still some steps and hints(conclusion)that I learned from Ms. Burton’s class:

1. Pick one equation and rearrange so it is x= or y=
2. substitute this into the other equation (use brackets)
3. solve it
4. substitute the number just found, back into the rearranged equation
5. verify solution