# Pre-Calc 11: Week 14 Multiplying and Dividing Rational Expressions

Last week in Pre-Calculus 11 we learned about multiplying and dividing rational expressions. A thing to remember about expressions is that it does not have an equal sign and you do not need to solve, you only need to simplify. I will be teaching you what non-permissible values are and how to determine what they are.

Non-permissible value :  Values that cause the fraction to have a denominator with a value of zero. (In math, we cannot divide by zero).

Here is an example of multiplying rational expressions

Steps:

Step 1:  Simplify $\frac{3x}{2(x-3)}\cdot\frac{8(x-3)}{9x^2}$ Non permissible values: $x\neq -3$

• $\frac{3x}{2(x-3)}\cdot\frac{8(x-3)}{9x^2}$
• remove (x-3) from top and bottom because they cancel eachother out
• then it becomes… $\frac {3x}{2}\cdot\frac{8}{9x^2}$

Step 2: Simplify by multiplying across (Just do it) • $\frac {3x}{2}\cdot\frac{8}{9x^2}$
• $\frac{24x}{18x^2}$

Step 3: Take the highest common factor from both the numerator and the denominator.

In this case 6 is the highest number that goes into both.

• $\frac{24x}{18x^2}$
• $\frac{4x}{18x^2}$ Step 4: Notice that x is on the bottom and the top, if it has a pair it can cancel out. two x’s on the bottom one on the top. when they cancel out each other you will be left with only 1 on the bottom.

• $\frac{4x}{3x^2}$
• $\frac{4}{3x}$ Final Answer: $\frac{4}{3x}$

Dividing Rational Expressions

There are many steps when dividing rational expressions

1. Simplify the fraction: can factor or take out the common denominator.
2. State the non permissible values.
3. Reciprocate the second fraction and it will because a multiplication expression.
4. State the restrictions again because there are new values in the denominator and could be non-permissible.
5. Simplify (cancel out like terms that have a pair on the numerator and denominator.
6. Multiply across (Just do it)
7. Simplify again if possible.

Step 1: Simplify $\frac{x+5}{x-4}\div\frac{x^2 - 25}{3x-12}$

FACTOR:

• $\frac{x+5}{x-4}\div\frac{x^2 - 25}{3x-12}$
• $\frac{x+5}{x-4}\div\frac{(x+5)(x-5)}{3(x-4)}$

Step 2: Non-permissible values

• $x\neq 4$ Step 3: Reciprocate

• $\frac{x+5}{x-4}\div\frac{(x+5)(x-5)}{3(x-4)}$
• $\frac{x+5}{x-4}\cdot\frac{3(x-4)}{(x+5)(x-5)}$ Step 4: Non-permissible values

• $x\neq 4$
• $x\neq 5$
• $x\neq -5$ Step 5: Cross out like terms

• $\frac{x+5}{x-4}\cdot\frac{3(x-4)}{(x+5)(x-5)}$
• $\frac{3}{(x-5)}$ Step 6: Multiply across if possible

• In this example it is not Step 7: Simplify further if possible

• In this example it is not Final Answer: $\frac{3}{(x-5)}$

This is how you Multiply and Divide Rational Expressions