My Arithmetic Sequence: 12,18,24,30,36

How to find:

t_{50}=t_{1}+(n-1)(d)

t_{50}=12+(50-1)(6)

t_{50}=12+(49)(6)

t_{50}=12+294

t_{50}=306

 

 

How to find:

t_{n}=t_{1}+(n-1)(d)

t_{n}=12+(n-1)(6)

t_{n}=12+6n-6

t_{n}=6+6n

 

 

How to find:

S_{n}=\frac{n}{2}(t_{1}+t_{n})

S_{50}=\frac{50}{2}(12+306)

S_{50}=25(318)

S_{50}=7950

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