All posts by Eyden

Week 10-PreCalc 11- Graphing Quadratics

This week in math ten we started graphing quadratics. I liked graphing last year so i was more so excited for this unit but it’s been difficult then i thought. What was difficult for me this week was remembering the difference between stretch, reflection and vertex. I didn’t understand how they all related and it was making me very confused when we began graphing using these numbers

Week 9- PreCalc 11- Midterm Review

A mistake I made this week that helped me learn while reviewing for my midterm was when rationalizing the denominator. I wasn’t aware that when rationalizing the denominator in a question like :

5√5/4√5

I did not keep the 4 connected to the √5 when multiplying the top and bottom by the conjugate which is wrong. Therefore I got the wrong answer. Instead I should have multiplied both by 4√5 resulting in the top of the equation being:

-20√25/-16√25

then,  square root 25 which equals 5

-20×5/-16×5= -100/-80 = 50/40 = 25/20 = 5/4

Week 8- PreCalc 11- Quadractic Functions and Equations

This week in Math 11 I learned about Quadratic Functions and Equations. My mistake of this week was while factoring  80x^4 – 5. I got to factoring it to 5(16x^4 – 1), but then I stopped there. I should have kept going as it can be factored more. I could have factored the 16, resulting in 5(4x^2-1)(4x^2+1)

In the future I shouldn’t stop after one step and make sure I am completely done before finishing the question.

Week 7- PreCalc 11- Solving Quadratic Equations

This week in Precalc 11 we learned about solving quadratic equations. While doing this I was severely overcomplicating how to solve for x. An example was when I was given the question:

x² – 3x + 2 = 0

When solving this I was not aware that you can just factor and solve for x by looking for what would make the equation equal to 0. Instead I was moving things around, switching signs and was very confused all around about what to do. To simplify what you can do is factor as usual …

x² – 3x + 2 = 0

= (x -2) and (x – 1)

And then when solving to find to make the equation equal to 0 just take x and figure out what would make (x -2) and (x – 1) equal to 0. Which is, 2 and 1.

Therefore,

{x= 2, 1 }

 

Week 5- PreCalc 11- Solving Radical Equations

When solving radical equations for this unit, I had no idea that you were supposed to square both side if there was a square root attached to a number with x. Instead I was dividing by the square root and then trying to rationalize the denominator on the other side to make it “nice” and both sides even. I was overcomplicating it much more then I had to however because instead I could just square both sides which results in the radical on one side of the equal sign disappearing and just with a bigger number on the other side. Then for the most part you can just divide both sides of the equal sign by whatever coefficient is attached to the x.

Example:

√4x = 2

Square √4x and 2

(√4x) x (√4x) = 4x and 2 x 2 = 4

Divide both sides by the coefficient attached to x (4)

4x/4 = 4/4

x= 1

Week 4- PreCalc 11- Dividing Radicals

My mistake that I chose for this week was not rationalizing the denominator when simplifying a fraction under the radical symbol. When doing the question given instead of reducing the numbers if I could then rationalizing the denominator to get rid of the radical I simplified and put another fraction on the outside, getting the wrong answer with two fractions, one as a coefficient, one under the radical symbol. Instead I needed to reduce the fraction if I could and rationalize the denominator then multiply the numerator of the fraction by the denominator as well.

Example:

√27/10

I needed to reduce the √27 to 3√3 and then multiply that by √10 as well as the denominator receiving 10 because √10 x √10 = 10

then getting the final answer as 3/10√30 as my final answer

Week 3- PreCalc 11- Adding and subtracting radicals

One mistake I made this week in the Adding and Subtracting Radicals unit was not knowing that with the same base underneath the radical sign you can just add or subtract the coefficients on the outside of the radical symbol, keeping the bas the same and get the right answer. I was under the impression I would have to convert the mixed radical to a entire radical to properly solve the equation, however I was overcomplicating it.

For example:

7√3 + 5√3 = 12√3

7√3 – 5√3 = 2√3

As shown above you can just add/subtract the coefficients/numbers in front of the radical sign when you have the same base under the radical symbol, and you get the right answer.

Example:

Week 2-Precalc 11-Rational Exponents

I chose to use determining the values of numbers with negative fractions for exponents. When I first encountered a question like this, because I was away the day we learned how to solve them, I thought I could just put the number and fractional exponent under 1 like you do with all negative exponents and be done with it, without finishing the rest of the equation. However I still needed to square root it by the denominator because it was 2 and it was easier because the numerator was 1, leaving it with the final answer being 1/3 simplified.