The general equation of a slope is y = mx+b, when solving the y-interpret. How would you do so?

This is an example that have been given to allow us to solve the equation.

You could find that the y-intercept is at the origin spot of (0,0), because the point is touching at the vertical line of the graph to tell that it’s (0,y). Whereas, we have the slope is 3/2x, as we have learned through the rise and run of our equation in our lesson. Therefore, our general equation to this answer is y = 3/2x. 

It’s up to you to find the x—intercept, but we would do our equation to replace the y-variable as zero to help us isolate to find our answer. Such as, y = 2/3x-6 to 0 = 2/3x—6, which we would algebraically use our linear’s knowledge to add six by both sides. It would give us to 6 = 2/3x, where you would multiply together to get 18 = 2x, and to divide by the coefficient. Our final answer would be nine as our x-intercept to this question.

So, what is a collinear? It means most of the points are laying on a single line.

 

The other equation to present is the point-slope intercept. That sounds interesting, but what could that apply to our math skills?

Their general equations that we shouldn’t mess up is m(x-x₁) = (y-y₁). Where you would have the slope (m) and the coordinate of your chosen would be the domain and range value. This could either be multiplied to solve your answer through the slope and your y-intercept.

What happen if you saw an epression of (-2,4) , 1/2, and it ask you for the point-slope intercept? What we have learn through the basics that we would do 1/2(x-(-2)) = (y-4), which we do the diustubrutive property on the brackets with the vairables. This would allow us to solve as 1/2x+1 = y – 4, where we would add four by both sides, because we want our y-variable to be alone.

This would give our answer to 1/2x + 5 = y, then we could check on our graphing caculator to verify that our answer is realted to our expression when given.

 

On the other hand, this unit is mostly about identifying our parallel and perpendicular through their slopes of the equation:

When the line intersects as a ninety degree, we can tell that they are perpendicular though their slopes with their reciprocal. It involves to have an opposite integer to their slope. Whereas, the parallel have the exact slopes of their appearance, because their lines are equal. Which means it would display with their y-intercept that could differ to the other. Their formula would include to have m1 = m2, it’s like having a twin!