This week I learned how to use elimination to get to the “special” point on a graph (the point where 2 lines intercept)

You take 2 equations

2x+y=10

5x-y=4

and then you add them together! Which equals to (7x=14) or simplified is (x=2), because positive “y” and negative “y” are zero pairs.

And then you do the same thing to find the (y=?) but this time there isn’t a zero pair to easily get rid of the “x” so you can multiply both equations to make them zero pairs.

5(2x+y=10) =  10x+5y=50

-2(5x-y=4) =  -10x+2y=-8

Which equals (7y=42) and then simplified equals to (y=6)

So the “special” point on this graph would be (2,6).