Week 8 – Properties of Quadratic Formula

This week, I learned how to use the table of values in a quadratic formula to find the vertex, x-intercepts, y- intercepts, range, domain, line of symmetry, whether if its maximum or minimum and direction of parabola.

A formulas we could use are y=a(x-p)^2+q and y=(x+b)(x+c)

The vertex of the quadratic is at (p, q) and for the second formula, we know that x can be -b or -c. We could find a by plugging the points.

This method helps us to draw the graph easily.

Week 7- Discriminant

This week, I’ve learned how to find discriminants. To find discriminant, you take the b^2 – 4ac from the quadratic formula. The discriminant shows how many roots the quadratic equation is going to have. If its positive, it will have 2 roots, if its 0, it will have 1 root, and if its negative, there are no roots.

Using this method, its going to save more time finding which equation works.

Week 6- Quadratic Formula

Quadratic Formula is a formula used when solving irrational equation or equations that can’t be factorized.

 

This week, I have learned a new method to factor. Its called quadratic formula. Its somehow easier and convenient to use than factorization as long as you know the formula.

The first step when using this formula is to find what a, b, c are.

For example,

x^2-12x+36

a would be 1

b would be -12

c would be 36

when plugging all these numbers into the formula, it would turn out to be

x=-(-12)+/-sqrt{-12^2-4(1)(36)}div 2(1)

x=12+/- sqrt{144-144}div 2

x=12div 2

x=6

Week 5 – Factoring Polynomial Expressions

Factoring Polynomial is a chapter that comes after Radical chapter. It shares the same law as the Radical chapter. However, in this chapter we are breaking the radical forms by factoring it. Most of the questions consist of factoring trinomial, determining if a given binomial is a factor of a given trinomial and etc…  Rationalizing, conjugating, and foiling is used in this chapter.

For example,

X²-4 = ( X+2)( X-2)

In this equation, I basically used the method of conjugating and rationalizing by cancelling positive and negative 2x as I know that X times 2 is 2X and X times -2 is -2X which cancels out when added together.

Week 4 – Radicals

In finding radicals, we use addition, subtraction, division and multiplication.

When adding and subtracting, the coefficient are combined when the radicand are the same. The strategies for simplifying polynomials can be used to simplify sums and differences of radicals

For example,

√3 + 2√7 + 4√3 = √3 + 4√3 + 2 √7 = 5√3 + 2 √7

When multiplying a radical, foiling is necessary

For example,

a√b * c√d = ac√bd

When dividing a radical, conjugating is necessary

No √ in denominator.

For example, \frac{2}{\sqrt{3}} = \frac{2\sqrt{3}}{3} as we multiply √3 on denominator

It is always important to simplify and removing square from radicand. It is going to make it easier to calculate.

Week 3 – Absolute Value

Absolute Value of a real number is defined as the principal square root of the square of a number.

For example,

-2 and 2 located 2 units from 0.

So, each number has an absolute value of 2.

|-2| =2

|2| =2

Absolute Value can be used to determine distance between two points

For example,

3-(-4) = 7, -4-3=-7

Since the distance cannot be negative, we rewrite the distance as an absolute value

|3-(-4)|=7, |-4-3|=7

The distance between two numbers on a number line is the absolute value of their difference.

We know that |a-b|=|b-a|

Week 2-Infinite Geometric Series

Infinite Geometric Series focuses on finding the sum of an infinite geometric series

The rules of this chapter is that

If…

r is r<-1 or r>1, it has no answer as the graph is diverging which means that the sum is getting bigger in positive and negative ways.

In other case,

r is -1<r<1, it has sum but the graph gets smaller.

For example…

8 + 2 + 0.5 + 0.125 + …

The common ratio is \frac {1}{4}

The formula used to find the answer is

S∞ = \frac {a}{(1-r)}

So, the answer would be 10.666666666… as S∞ = \frac{10}{1-(\frac{-2}{3})} =6

In this chapter, it is very important to identify the range of the “r” value.

Week 1-My Arthmetic Sequence

In this week, we have learned about sequence and series which basically is finding a pattern with common difference with before and after numbers. For example,

  1. t_1=3
  2. t_2=-1
  3. t_3=-5
  4. t_4=-9
  5. t_5=-13

We can know from here that the common difference is -4 and we can know that the first number which is t_1 is 3.

Sum of all 50 numbers S_{50} would be 4850 as t_{50} is -193 and when we apply n=50, t_{50} which is -193 and t_1 which is 3, into Sn=\frac{n}{2}({t_1}+{t_n}) , S_{50} would be equavalent to 4850

It is important to have no calculation mistake in this chapter as it might affect greatly on our resultant value