Week 9 – Precalculus 11 – Vertex and Parabola

Example: y=\left(x-5\right)^{2}-9, we need to start by identifying the parts of the equation.The question contains an x^2 which means we have a parabola. We have to make both sides zero, so instead of -5, it’ll become positive 5. The value inside the bracket, that being -5 is the x value and the number outside the brackets, that being -9 is our y value. When graphing the vertex we go along positive 5 on the x axis and then down -9 on the y axis. Because the equation does not have a coefficient outside the left of the bracket, there is no stretch. The graph will then follow the parent function of 1-3-5. Once graphed it will look like this:

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