This week I learned how to calculate the surface area and volume of spheres this can be useful if we’re calculating a round object or like a rounded top think like a lid of a pot.

In the example above the question says ” A boiler in the shape of a cylinder with hemispherical ends. Its total length is 14 m and its diameter is 6m. Its cubic content, to the nearest m^3″. If Both ends are hemispheres that will be a total of 1 sphere in whole so the forumla is 4/3 (pi)(3)^3 which is 113.1m^3. Next step is the volume (pi) r^2H (r = radius, H = Height) so if the diameter is 6 the radius is 3 and the height would be 8 and that is because both sides are hemispheres we dont include them in the measurement so it is (pi) (3)^2(8). = 226.19 + 113.10 = our result when rounded up 339m^

This class we learned how to turn a certain measurment into another. So we were able to convert metric units to Imperial and vice versa.

In this example it wanted me to convert 0.4miles into inches so what I did was change miles into feet and then feet into inches and to do so above I took miles and put it in the denominator as 1 mile and how many feet are in a mile? 5280 and how many inches are in a foot? 12. So with all the calculations and crossing things out it turns into 0.4 x 5280 x 12 which is 25344 and we wanted inches so that’s what we kept.

solving for when your exponent is a fraction is easy. as shown above you take the equation and put it into a radical equation. So what you do with the fraction is you take the denominator and make it the index and then you take the numerator and make that an exponent for X. And of course B cannot be 0.

the above image is an image of changing mixed radicals into entire so like to do this you have to is put the coefficient into the square root (4) so you square root 4^2 (to the power of 2) (as shown above) then you calculate the square root which is 16 and then inside the square root you do 16 x 5 which is 80 so 4 x the square root of 5 is equal to square root 80.

Starting this class was a blur after the summer and everything so I totally forgot about factors. But this week I re learned about factors and prime factors. Prime factors are the numbers that can only work if they are devided by itself or 1. so something like 2 or 13. I also found out how to find prime factors using a number tree.