5 things I did to succeed in math 10.

1. the most obvious thing to do is just pay attention in class! You’re not going to learn anything sitting on your phone all class.
2. Come to the teacher for help. I’m guilty of not doing this but going to your teacher after class can really help you.
3. Study before the night before the test. Again i’m guilty but, studying is really helpful and it wont make much of an impact unless you study over multiple days a little bit at a time.
4. Sit where you can easily see the board. I’ve seen many people sit in the corners where its just more difficult to see! try and sit in the middle so you get a good POV over the board.
5. Remember your calculator on test days. Not all teachers will hold your hand you have to bring what is needed for a test or exam if you show up empty handed the teacher wont care.
6.  (BONUS) Do your homework, homework is not obligatory but it will help you if you’re not understanding what you’re doing!

Here is my graphing project for this week in math 10.

This week in Math 10 we learned how to calculate slopes using a formula, the slope formula is it does not matter what number you choose for what as long as you keep it the same and dont change it.  You need 1 x coordinate and 1 y coordinate. so if we have our numbers as (-5), (-7) and (5), (3) then the equation would be so it easily comes out as . which is = to 1.

This week in math 10 we learned about domain and range with coordinates and on a graph.

The range is the set of all y values and the domain is the set of all x values. on a graph if the domain was 1 and the range was 3 the coordinate on a graph would be (1, 3).

This week, we learned how to find X and Y intercepts, we use these to find out what Y is when X = 0 or vice versa. To find out what X intercept is set Y to 0. and solve.

If we have an equation like  3y = 5x + 15 we’ll replace with 3(0) = 5x + 15. now to solve this we will need to bring 15 to the opposite side. so the equation looks like -15 = 5x then to get rid of 5 we will need to divide 5 from each side. so we have -3 = x so the coordinate would be (-3, 0) simple.

This week we learned how to factor trinominals that have a coefficient that is not 1 in the 1st term. We have been taught the area module and the guess & test way but Im going to show the area module . In this example we have – 8x + 1 . Step 1 draw a box and divide it into 4 equal sections. Step 2 put the first term in the top left box and the last term in the bottom right. Now on the outside right down the first term multiplied by the last term which = then below it put the middle term. so that you know what numbers to work with. then find 2 numbers that multiply to and add to – 8x.  here we can do (-2x) (-6x) so we put them in the two blank spots in the box. then the last thing to do is put the answers you recieve into brackets which would be (2x – 1) and (6x – 1) always put the number in descending order according to the degree of the exponent.

This week we learned how to factor a difference of squares, for example – = (a – b) (a + b) for a difference of squares to be a difference of squares, both sides must be… squares, perfect squares.  so if we have + we can square root it and we`ll have ( x – 3y) (x + 3y) the first bracket is subtraction and the second one is additon and if its a difference of squares it must have both. And that`s how you factor a difference of squares

This time in math we learned how to find the greates common factor of a polynominal. If we get something like (5 ) (15 y) then first we start with the coefficients and so between 5 and 15 5 is the gcf and for exponents it is whatever has the lowest exponent. so then u add them together so we`ll have 5 y. We have to divide the remainder so we’ll get 5 y () (3x) and there is our anwser for how to find the GCF.

This week we learned how to use foil to solve binomial equations.

In the question above it asked for (x + 6)(x – 2)

This is a simple question to solve if you follow FOILs directions. F : first term in each bracket. So that would be X x X which would be . O : Outside terms. Which would be X x -2 = -2x. I : inside terms. 6 x X = 6x. L : Last terms. 6 x -2 = -12. At the end we would have – 2x + 6x – 12. and if we added like terms it would be; +4x – 12.

In the trigonomerty unit we learned SOH CAH TOA Which is basically how we will calculte most things with right angle triangles.

In the example above the question is asking for the height of both buildings and giving you these numbers : looking up to the taller building from the lower bulding is 24 (degrees) and the angle of depression is 56(degrees) and the buildings are 45m apart. The question asked for the height of both buildings and the way to find it is through SOH CAH TOA You have to find what parts are the triangles (both triangles) (Opposite, Adjacent, Hypotenuse) for the bottom triangle the top line is the adjacent the right line is the opposite and the hypotenuse is the left line. If we are trying to find the building heights we need the OPPOSITE side and to find that we need TOA which is Tan(56degrees) = (x / 45) then u times each side by 45 so 45 x Tan(56degrees) = x and u punch that in that equals 67 m. That is the height of the small tower and part of the taller tower.