April 24

Week 10 – Difference of Squares (Factoring)

This week we learned how to factor a difference of squares, for example a^2b^2 = (a – b) (a + b) for a difference of squares to be a difference of squares, both sides must be… squares, perfect squares.  so if we have x^2 + 9y^2 we can square root it and we`ll have ( x – 3y) (x + 3y) the first bracket is subtraction and the second one is additon and if its a difference of squares it must have both. And that`s how you factor a difference of squares

April 14

Week 9 – GCF of Polynominals

This time in math we learned how to find the greates common factor of a polynominal. If we get something like (5 x^2 y^5) (15 x^3 y) then first we start with the coefficients and so between 5 and 15 5 is the gcf and for exponents it is whatever has the lowest exponent. so then u add them together so we`ll have 5x^2 y. We have to divide the remainder so we’ll get 5x^2 y (y^3) (3x) and there is our anwser for how to find the GCF.

April 7

Week 8 – FOIL

This week we learned how to use foil to solve binomial equations.

In the question above it asked for (x + 6)(x – 2)

This is a simple question to solve if you follow FOILs directions. F : first term in each bracket. So that would be X x X which would be x^2. O : Outside terms. Which would be X x -2 = -2x. I : inside terms. 6 x X = 6x. L : Last terms. 6 x -2 = -12. At the end we would have x^2 – 2x + 6x – 12. and if we added like terms it would be; x^2 +4x – 12.

April 3

Week 7 – SOH CAH TOA Calculations

In the trigonomerty unit we learned SOH CAH TOA Which is basically how we will calculte most things with right angle triangles.

In the example above the question is asking for the height of both buildings and giving you these numbers : looking up to the taller building from the lower bulding is 24 (degrees) and the angle of depression is 56(degrees) and the buildings are 45m apart. The question asked for the height of both buildings and the way to find it is through SOH CAH TOA You have to find what parts are the triangles (both triangles) (Opposite, Adjacent, Hypotenuse) for the bottom triangle the top line is the adjacent the right line is the opposite and the hypotenuse is the left line. If we are trying to find the building heights we need the OPPOSITE side and to find that we need TOA which is Tan(56degrees) = (x / 45) then u times each side by 45 so 45 x Tan(56degrees) = x and u punch that in that equals 67 m. That is the height of the small tower and part of the taller tower.

April 3

Week 6 – Spheres (Surface Area and Volume)

This week I learned how to calculate the surface area and volume of spheres this can be useful if we’re calculating a round object or like a rounded top think like a lid of a pot.

In the example above the question says ” A boiler in the shape of a cylinder with hemispherical ends. Its total length is 14 m and its diameter is 6m. Its cubic content, to the nearest m^3″. If Both ends are hemispheres that will be a total of 1 sphere in whole so the forumla is 4/3 (pi)(3)^3 which is 113.1m^3. Next step is the volume (pi) r^2H (r = radius, H = Height) so if the diameter is 6 the radius is 3 and the height would be 8 and that is because both sides are hemispheres we dont include them in the measurement so it is (pi) (3)^2(8). = 226.19 + 113.10 = our result when rounded up 339m^

April 3

Week 5 Converting Metric and Imperial with Unit Analysis

This class we learned how to turn a certain measurment into another. So we were able to convert metric units to Imperial and vice versa.

In this example it wanted me to convert 0.4miles into inches so what I did was change miles into feet and then feet into inches and to do so above I took miles and put it in the denominator as 1 mile and how many feet are in a mile? 5280 and how many inches are in a foot? 12. So with all the calculations and crossing things out it turns into 0.4 x 5280 x 12 which is 25344 and we wanted inches so that’s what we kept.