This week I realized I didn’t actually know how to convert a quadratic function from vertex form into general form. the first step is always to deal with the squared bracket. For example, if the equation is y = 2(x-3)² + 8, the correct way to begin is to rewrite the squared part as (x-3)(x-3). That changes the equation into y = 2(x-3)(x-3) + 8, which puts it in a more expanded form and makes it much easier to find the stretch of the function and also the Y intercept. From there, you just foil the two “(x-3)” and then after distribute the 2 into the quadratic to get rid of the brackets and then combine the +8.