We learned how to solve systems which are just two equations that cross on the same line.

There are four way to solve these systems substitution, elimination, graphing, or inspection.

I am going to use substitution to solve this system.

2x+2y=8

x+3y=14

First you want to move the y to isolate the x because that will be the first coordinate we will be finding.

2x=8-2y

now you have to fully isolate the x by dividing by 2 from the entire equation.

x=4-y

place the x into the second equation where the x is located.

4-y+3y=14

move the like terms together.

-y+3y=14-4

2y=10

now divide again to isolate the x

x=5 is your x coordinate.

now to place that into the y in either equation you find easier

i will be using x+3y=14

x+3(5)=14 multiply 5×3

x+15=14

now move like terms together

x=14-15

x=1

and your final coordinates will be (-1,5)