Using the SOH CAH TOA methods we can solve these triangles. For the first triangle we can see that the variable is in the top angle and we are given the hypotenuse side length(14) and the adjacent side length(3.5). Using this data we use CAH to solve for the variable, as shown in the first work. For the second triangle the variable is the opposite side length, and the given numbers are angle 53° and 3 for the adjacent side length. With this data we can use TOA to solve for x, as shown in the second writing. For the third triangle we can see that the variable is in is in the side angle and we are given the hypotenuse side length(10) and the opposite side length(7). Using this data we use SOH to solve for the variable, as shown in the third work.
April 11, 2016 at 9:36 pm
You are missing the type of equation that is missing a side that is located on the bottom of the fraction on the right. Please update and repost.