Week 11 – Quadratic Inequalities with One variable

Review: 4x-5<11 (you just solve to find x) so 4x<16 => x<4. If diving by negative you must switch sign.

You do the exact same solving for quadratics.

x^2-8x+16>0 Factor= (x-4)^2  then zero product so x=4 then you test a number greater and smaller then 4 in the original equation to see what the restriction is and if the solution is true.

Try 0 (if you can)

0^2-8(0)+16>0 => 16>0 which is true

Try greater number: 5 in this case

5^2-8(5)+16>0 => 1>0 which is also true

 

So the solution/restrictions are x<4 and x>4 to make this quadratic equation true.

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