# Week 6 – Discriminant

Exp. $5x^2+4x-9$

a=5
b=4
c=-9

Put these values into the $b^2-4ac$ part of the quadratic equation.

$4^2-4(5)(-9)$

16-4(-45)

16–180

16+180=196

In this case the discriminant is positive so there would be 2 solutions for the quadratic equation. If it were to be negative there would be no solution and if it was equal to zero their would be one.