Precalc 11 – “Week 13”

This week in Precalculus 11 we learned about Absolute Value Functions. We have already done absolute values which is:

\mid-3x+5\mid=11

Which is 3x=6

x=2

Absolute values turn the equation positive. Therefore an Absolute Value Function can only be positive.

y=\mid-3x+5\mid

As you can see the blue line is y=-3x+5, and because absolute values need to be positive then the line cannot be below the x-axis, therefore it is flipped as you can see by the red line: y=\mid-3x+5\mid

Thank You for Reading!

Precalc 11 – “Week 12”

This week in Precalculus 11 we learned about how to solve quadratic systems.

Most questions were based on two lines either quadratic-quadratic or linear-quadratic.

There are multiple ways of find the solution for where both lines cross, like graphing or elimination. However in class we learned about the process of substitution.

Which is removing one variable from the equation and then solving for the remaining unknown variable. After that using that answer to find the first unknown variable.

ex.

y=2x+5

 

y=x^{2}+6x+9

 

2x+5=x^{2}+6x+9

 

0=x^{2}+4x+4

 

x=2

 

y=9

 

Thank You for reading!

Precalc 11 – “Week 11”

This week in precalculus 11, we learned about graphing linear inequalities.

This is what we learn:

If the inequality was greater than or equal to y:

y=<2x+2, then you also need to shade the line.

Same goes for an inequality which is less than or equal to y.

However if it is only greater than or only lower than, then you must leave a dotted line to inform that the line does not count as part of the answer.

Thank you for reading!

Lord of The Flies – Morality Podcast

 

WORK CITED

Golding, William. Lord of the Flies. Penguin, 1983.

 

James, Wendy. Personal interview. 8 Nov. 2017.

 

Rosenfield, Claire. “‘Men of a Smaller Growth’: A Psychological Analysis of William Golding’s Lord of the Flies.” Literature and Psychology 11.4 (1961): 93-101.

The rest of the group, however, shifts its allegiance to Jack because he has given them meat rather than something useless like fire.

 

Crosser, Sandra. “Emerging morality: How children think about right and wrong.” Excelligence Learning Corporation. http://www. earlychildhood. com/articles/index. cfm (2014).

Gilligan’s point can be seen in children’s free play. When boys are confronted with a conflict involving fairness they tend to argue it out or take their ball and go home. On the other hand, girls faced with conflict over fairness will try to resolve the issue through compromise. But if compromise fails, girls will generally change the activity rather than disband the group (Cyrus, 1993).

 

Service, Indo-Asian News. “Herd Mentality: Even Kids Know to Agree with the Majority.”

These results indicate that children as young as age three and four are able to recognise and trust a consensus. In addition, young children are good at remembering who was and was not a part of the majority group, said a Harvard release.

Baumrind, Diana. “Parental disciplinary patterns and social competence in children.” Youth & Society 9.3 (1978): 239-267

How Piggy had no parents, so he was really shy and did everything that the other boys did to fit in with the group.

 

“Peer Pressure in Preschool Children.” Max Planck Society,

Of 18 children 12 conformed to the majority at least once, if they had to say the answer out loud.

Precalc 11 – “Week 10”

This week in Pre-Calculus 11, we studied and reviewed for our midterms next week. The most challenging thing for me is how to find t_{8} when you only know t_{2}=10 and t_{4}=20.

With the help of some of my classmates, we realized 4 divided by 2 and 20 divided by 10, would give us the d value. by dividing those two answers: 10 divided by 2, it gives the d value which is 5. Then using the arithmetic formula you can find t_{1}=5 and then t_{8}=40.

Thank you for reading and good luck on your midterms!

Periodicity

A.

  1. Rubidium (Rb)
  2. The more electrons there are on one shell the smaller the atomic radius,  That is why for the first family the atomic radius is big. Every period the atomic radius increases in proportion to the last period.
  3. a) Cesium (Cs) -> 0.295 nm       b) Tungsten (W) -> o.135      c)Thallium (Tl) -> 0.180       d) Radon (Rn) -> 0.140
  4.  Group one contains the largest elements.

B.

  1. The amount of energy needed to remove the looses electrons.        a) By period it increases until it gets to the noble gases, and then the next element decreases drastically, because the valence shell is not complete. By family it decreases one by one.       b) Helium (He).
  2. a)[Ne] 3s2 3p5             b) The last electron, the electron configuration would look like this: [Ne] 3s2 3p4.
  3. For metals the ionization energy is closer in between each element, and for the nonmetals the ionization energy varies drastically. Metals tend to have lower ionization energy than nonmetals.

C.

  1. Within a period the melting point usually increases until it reaches the fourth group, after this point the melting point decreases, however for the metals this changes.
  2. The fourth group.
  3. Carbon could be a reasonable change for Tungsten, because it has a very high melting point.

D.

  1. By period we can see that it increases then decreases and the increases and finally decreases one last time when it reaches the noble gas. This is visible on the graph.
  2. The densities a very similar if we look at their group and density, meaning Berium has a similar density to Magnesium.
  3. The metals generally have a larger density than the main group, with some metals having more than double the density of the main group.
  4. Aluminum and Magnesium are more suitable for airplane parts, because they are less dense than iron which is almost twice their density.

E.

  1. Within period, the electronegativity increases drastically.
  2. Within group, the electronegativity decreases slowly.