How does one find an angle using the hypotenuse and the adjacent? It’s e
asy! Ratio (reference angle)= side 1 over side 2. Find the equation that uses the hypotenuse and the adjacent. In this case, it’s cosine. First step: The cosine of the reference angle (x) = 20 over 23. Second step: get x by itself (isolate x). By doing that, you have to bring cos to the other side, but something goes to the other side, it because the opposite therefore; you have to make cos negative. Now you multiply everything together to find x!
asy! Ratio (reference angle)= side 1 over side 2. Find the equation that uses the hypotenuse and the adjacent. In this case, it’s cosine. First step: The cosine of the reference angle (x) = 20 over 23. Second step: get x by itself (isolate x). By doing that, you have to bring cos to the other side, but something goes to the other side, it because the opposite therefore; you have to make cos negative. Now you multiply everything together to find x!How does one find the hypotenuse when all that is given is the reference angle 
(30 degrees) and a side length (adjacent=20cm)? First step: find an equation. The equation that fits is the cos30=20 over h. Since we don’t know what h is, you have to reciprocate it, but what you do to one side, you have to do the same thing to the other (reciprocate the other side). h=20 over cos30.
(30 degrees) and a side length (adjacent=20cm)? First step: find an equation. The equation that fits is the cos30=20 over h. Since we don’t know what h is, you have to reciprocate it, but what you do to one side, you have to do the same thing to the other (reciprocate the other side). h=20 over cos30.How does one find the opposite with just the reference angle and the adjacent. Find the equation that fits. In this case, it’s tan30=g over 20. T
he common denominator for both is 20 so multiply both by 20. The 20s on the right side of the equation cancel each other out and what’s left is 20(tan30)=g.
he common denominator for both is 20 so multiply both by 20. The 20s on the right side of the equation cancel each other out and what’s left is 20(tan30)=g.