Trigonometry

In math class I’ve learned how to find a missing angle as well as finding a missing length of a right angle triangle using trig functions (sin, tan and cos) and learned about how to find the angle of elevation and depression.

To find an angle of a right angle triangle, you always need to have two sides of the triangle. You then start labelling the sides of the triangle so you can see which trig function to use:

Adjacent: the side near the degree.

Hypotenuse: the longest side of the triangle and is opposite to the 90 degree angle.

Opposite: the length that’s opposite to the angle.

After labelling the triangle, you then figure out which sides and angles are given:

Sine: \frac{opp}{hyp}

Cosine: \frac{adj}{hyp}

Tangent: \frac{opp}{adj}

Punch in the two sides given depending on the trig function you are using, then press 2nd function then the trig function (Sin, Cos, Tan).

If you are given an angle and a side length and you need to solve a missing length, you first label the sides, figure out which length and angle you have then find the function you need to use which includes the side given and the side you are looking for and put it into your calculator depending on the function you are using.

Example: function (x) = \frac{length given}{length you are looking for}

 

The hardest part about this lesson was the problem solving questions. It’s hard for me to put the information given into a diagram/drawing because I sometimes mix up the sides on where it’s supposed to go.

Surface Area and Volume

This week of math class, I’ve learned how to find the volume and the surface area of prisms, cones, pyramids and spheres, as well as learned some new formulas that I can utilize.

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Here I am looking for the volume and surface area of a prism. In this example, I needed to use Pythagorean Theorem because the height length was not given to find the area of the triangular base. The whole idea of Surface Area for prisms is to add all the areas of the surfaces/faces. It’s different for cylinders, cones, spheres and pyramids, instead they each have their own formula:

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The most challenging part about learning this lesson was finding the Surface Area because it requires a lot of steps and you can accidentally make a small mistake which changes the answer completely. For example, sometimes I would accidentally add the same side of the shape twice or consider the slant height as the height.

Imperial and SI systems

There has been quite a few things I’ve learned from Imperial and SI systems. I’ve learned more different conversions in measurements such as converting from feet to miles and meters to yards as well as how to apply them to real life situations. I’ve learned how to do conversions when it includes more than one type of measurement like 2 mi 325 yds to yards. I’ve also learned how to read a vernier caliper in Imperial and metric units and how to read a micrometer in metric units.

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Here I am converting ft and inches into inches  by changing feet into inches then adding the other inches. 

When you are given multiple measurements, sometimes you have to do multiple conversions because some of the conversions are not given. For example meters to feet. You have to go through multiple conversions, meters to centimeters then to feet.

The challenges I came across was the problem solving questions because I had a hard time applying the necessary measurements and what to do. It took some time to solve some of them but I managed to figure them out, although I still need some practice.

 

What I have learned in Math 10

These last few weeks of math have been interesting and educational. I’ve learned more about negative exponents and how to convert them into a positive exponent as well as how to deal with exponents in form of a fraction. I also learned how to find the Lowest Common Multiple and Greatest Common Factor in a quicker way using prime factorization which has helped me a lot in science when I needed to balance chemical equations.

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GCF/LCM

Finding the GCF and LCM 

GCF 

To find the GCF, you need to divide both numbers and write the number that is being divided equals to the number of times the second number can go into the first number (how many times 180 can go into 378), then add the remainder.

GCF of 180 and 378:

 

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Keep dividing until the remainder is 0. In this case, the equation left is 180 = 10(18) + 0, which means 18 is the GCF because 18 can go into 180 equally without a remainder.

LCM 

To find the LCM, you need to take both numbers and multiply them.

180 and 378

180(378) = 68 040

After you multiply both numbers, you then take the number and divide it by the GCF.

68 040/18    (18 is the GCF)

= 3 780

So the LCM of 180 and 378 is 3 780.

 

Between this method and prime factorization, I think prime factorization is better because it works for any amount of numbers given whereas this method only works with two numbers. Although, I would use this method if given two numbers because I find it quicker and easier for larger numbers.

Scientific Method Bubble Gum Lab

 

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Hypothesis: 

Bubble size relates to how far gum can stretch because the gum can’t increase in size if it can’t stretch.

Conclusion: 

In conclusion, the amount of stretchability reflects how big the bubble is. If the gum doesn’t have much stretchability, the bubble size is small because it’s hard for it to increase in size if it’s stretchability is small. Whereas gum that has lots of stretchability, the bubble size is bigger.

List 5 variables that may affect the outcome of this experiment: 

  1. The time on how long you chew it
  2. Size of gum
  3. The person who’s chewing
  4. Saliva
  5. Density of the gum

Explain how the data you collected can be described as both qualitative and quantitative: 

It can be described as qualitative by the stretchability and it can be quantitative by the size/mass and the amount of density in the gum.

Were SI Units used in this lab? Explain.

Yes, we used cm and m for measuring the bubble size and how far it can stretch.

In conclusion the Hubba Bubba made a bigger bubble than the Big League because it was more sturdy so it would expand more without popping.