**1**.I had some trouble with finding the vertex

**2.** *y* = 3*x*^{2} + *x* – 2

**3. **To find the vertex, I look at the coefficients *a*, *b*, and *c*. The formula for the vertex gives me:

*h* = ^{–b}/_{2a} = ^{–(1)}/_{2(3)} = ^{–1}/_{6}

Then I can find *k* by evaluating *y* at *h* = ^{–1}/_{6}:

*k = *3( ^{–1}/_{6 })^{2} + ( ^{–1}/_{6 }) – 2

= ^{3}/_{36} – ^{1}/_{6} – 2

= ^{1}/_{12} – ^{2}/_{12} – ^{24}/_{12}

= ^{–25}/_{12}

So now I know that **the vertex is at ( ^{–1}/_{6} , ^{–25}/_{12} )**.

At first i didn’t really know what the vertex was and now i know the its the highest or lowest point of the graph and this helps when I’m also trying to find the Domain and Range. (also learned Vertex form was really helpful)