week 15- precalc

rubeng2016 on December 16, 2018

This week in math we learned how to simplify an expression when they are adding.

$\frac{6}{a-3}+\frac{2}{a+7}$

The non-permissible values are A cannot equal 3,-7. The next step is to multiply both fractions by a common denominator

$\frac {6 \times (a+7)}{(a-3)\times (a+7)}+\frac{2\times(a-3)}{a+7\times(a-3)}$

$\frac{6a+42+2a-6}{(a-3)(a+7)}$

then collect like terms

$\frac{8a+36}{(a-3)(a+7)}$ is what you are left with

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