week 14 – Precalc

This week in math we learned how to simplify a rational expression and determine the non-permissible values. The expression below is an example of how to do this.

\frac {10y}{(y-3)^3}\div{\frac {y(y+1)}{(y-3)^2}}

The first step is to determine the non-permissible values which for now are only Y cannot equal 3.

\frac {10y}{(y-3)(y-3)(y-3)}\times{\frac {(y-3)(y-3)}{y(y+1)}}

Now that you have flipped the fraction you have to determine the new non-permissible values of the second fraction which are, Y cannot equal 0,-1.

you can now cross out the top of the fraction with the bottom of the fraction. Then you end up with:

\frac {10}{(y-3)(y+1)}

 

Leave a Reply

Your email address will not be published. Required fields are marked *