math 10 – week 15

We continued systems of linear equations but this week we learned to solve equations without a zero pair.  Say you are given the equation x+3y=4/2x+5y=1, we woild multiply the first equation by -2.  Now we have -2(x+3y=4)/2x+5y=1, if we do the distributing any multiply the first equation by -2 we get,  -2x-6y=-8 + 2x+5y=1, when we add these equations we get -y/-1 and -7/-1 therefore y=7.