this week in math 10 we started our unit on “systems of linear relations” I learned that a solution is the point on a graph at which two lines meet. depending on the relation of the two lines, there can be 1 system, infinite systems, or no systems at all. there is one system if the slopes to not match, there are an infinite amount if the slope and y-intercept of the lines match, and there are 0 solutions if the slopes are the same because this would represent parallel lines.
to find the solution of two lines we can use one of two methods, we can use the elimination method or the substitution method.
do demonstrate substitution for example we have the lines
8x-3y=10 , x-y=5
start off by choosing an equation of the two to isolate either y or x.
x-y=5 now turns into x=y+5
now we take the other equation 8x-3y=10, and replace x with y+5, becomes 8(y+5)-3y=10 , distribute the 8 into y and 5
8y+40-3y=10, combine like terms and isolate the variable to find the y coordinate.
8(y+5)-3y=10
8y+40-3y=10
5y=-30
5y/5=-30/5
y= -6
now to find the x-intercept we go back to one of the original equations and replace all of the y’s with -6
x-y=5
x-6=5
isolate the variable
x=-1 now we have the solution of these two lines as (-1,-6)
no verify this, we input the x and y into both original lines and if they are both equal then the question is complete
now to use elimination, a much quicker method.
we have the lines 2x+3y=7, 5x-3y=28
we can either add or subtract the two equations, the goal is to get two of the terms to cancel out to make the question simpler
2x+3y=7
5x-3y=28
add the equations together, in this case, +3y and -3y are opposites so they can cancel out and we are left with
7x=35 now isolate x
so x=5. now we input 5 into one of the original equations, replacing all of the x’s, to find the y-coordinate. then verify by inputting x and y into both original equations as we did for the substitution method.