## Week 3 in Precalc 11

Tell:

This week we just started to learn “Absolute Value and Radicals”. One thing that I have learned so far is how to solve an equation that is given with negative numbers and the sum will be positive, when place inside |  |  Absolute value braces / symbols.

Show:

here is one equation that I was stuck on because I didn’t place the right signs besides the numbers, which was giving me the wrong answer. Explain:

In this equation you plug in -3 where there is an x. The equation becoming $-3^3$ and -5(-3), getting results from those then solve the final equation. Equation will become a positive due to being inside the Absolute value braces.

## Week 2 in Precalc 11

Tell:

This week I have learned how to determine a certain value for different geometric sequences, by using specific formulas created to find those results.

Show: Explain:

In solving this problem you first need to find “R” by using the formula $\frac{t_2}{t_1}$. Once you have found “R”, you can determine $t_1$ by looking at the terms left to right. With all the information you have found now you can plug it all into the formula $t_n = t_1 * R ^(n-1)$. Using BEDMAS go step by step to find your answer.

## My Arithmetic Sequence $3,6,9,12,15$ $t{n}=t{1}+(n-1)(d)$ $t_{50}=3+(50-1)(3)$ $t_{50}=3+147$ $t_{50}=150$ $t_{n}=3+(n-1)(3)$ $t_{n}=3+3n-3$ $t_{n}=3n$ $S_{n}=\frac{n}{2}(2(t_{1})+(n-1)(d))$ $S_{50}=\frac{50}{2}(2(3)+(50-1)(3))$ $S_{50}=25(6+147)$ $S_{50}=25(153)$ $S_{50}=3825$