Day: November 19, 2018

This week we learned how to graph linear inequalities in two variables. A linear equation is a graph that splits into two sections.  A linear inequality looks very similar to a linear equation, the difference between the two is that a linear equation has a “equals” symbol and a linear inequality is divided into 4 groups: greater than, greater than and/or equal to, less than, less than and/or equal to. When writing or understanding a graph of a linear inequality, she will shade in or color in the side where the linear inequality is true. A solid line represents _____ and/or equal to. A checkered line represents ____ than. To find the region that will satisfy the inequality we choose a point (0,0 would be easiest) on its appropriate side and plug it into the linear inequality. Then solve the linear inequality. If the inequality sign is true to the numbers then shade in the region, if not shade in the opposite region on the graph.

Below is an example of how to graphs such equations:

Since the midterm was coming up, or rather has already passed, I decided to focus on what I had somewhat forgotten, which is what we first learned; geometric and arithmetic sequences. Since we learned the until months ago, I had forgotten some key information when having to solve for a series or sequence. I mostly forgot the naming and letters in the formulae. Being that Physics 11 has so many abbreviations, I got caught up in all of the ones I had already known. It was also good to review this chapter because when we don’t practice something constantly, we will eventually forget it.

Here is a link to help understand: http://discretetext.oscarlevin.com/dmoi/sec_seq-arithgeom.html

I studied thoroughly on infinite series and the rules and restrictions that come with it.  The sum of an infinite arithmetic sequence is a negative infinite number if d is less than 1, and a positive infinite if d is bigger than 1. There are two ways to find the sum of a finite arithmetic sequence. To use the first method, you must know the value of the first term (a₁), the rate at which it multiplies (r) and the value of the last term (a_n).  Then all you have to do is punch in the numbers into the equation. S_∞ = a₁ / (1-r ).

See this link to learn more : http://home.windstream.net/okrebs/page133.html