This week we started a brand new unit, Factoring polynomials. I’m very happy we stared this unit because this was one of my favourite units to do last year in math 10. We spent t most of the day on Friday when we started the unit doing review. Once I did the first question everything came back to me. In my opinion the easiest factoring to do is when you have perfect square binomials like  All you need to do is square root both numbers and put them in brackets. Example:

i got this answer because I put the square root of (x) at the beginning of each bracket. I then took the square root of 100 which is (10) and I put that at the end of each bracket. has a negative sign, that means that one of the 10 will be positive and the other one will be a negative becasue 10x(-10)=-100

When you are factoring trinomials like This trinomial is an easy trinomial because it has $larex x^2 at the front$ In order Govett solve this trinomial you need to find 2 numbers that multiply to 12amd add to 7. In this case we would use the numbers 3 and 4 because 3×4=12 and 3+4=7. These are the steps I take to get the answer

> we start with the original equation

&$atex x^2+3x+4x+12$ > we take our 2 numbers that multiply to 12 and add to 7 and we put them into our equation in replace of the 7 in order to expand

> we the night take the common factor out of each equation and put whatever is left over into brackets, in the step we should get the same numbers in both the bracket, I got (x+3)

> the 2 brackets turn into one and you take the common factor from each equation and put them into a bracket (x+4)