My Arithmetic Sequence

$-14, -2, 10, 22, 34$ …

Part: 1

$t_{n}=t_{1}+(n-1)d$

$t_{50}=-14+(50-1)(12)$

$t_{50}=-14+49*12$

$t_{50}=-14+588$

$t_{50}=574$

Part: 2

$S_{5}=\frac{n}{2}(t_{1}+t_{n})$

$S_{50}=\frac{50}{2}(-14+574)$

$S_{50}=25(560)$

$S_{50}=14,000$

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